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Simplifying 50 + 15c + c2 = 0 Solving 50 + 15c + c2 = 0 Solving for variable 'c'. Factor a trinomial. (10 + c)(5 + c) = 0Subproblem 1
Set the factor '(10 + c)' equal to zero and attempt to solve: Simplifying 10 + c = 0 Solving 10 + c = 0 Move all terms containing c to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + c = 0 + -10 Combine like terms: 10 + -10 = 0 0 + c = 0 + -10 c = 0 + -10 Combine like terms: 0 + -10 = -10 c = -10 Simplifying c = -10Subproblem 2
Set the factor '(5 + c)' equal to zero and attempt to solve: Simplifying 5 + c = 0 Solving 5 + c = 0 Move all terms containing c to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + c = 0 + -5 Combine like terms: 5 + -5 = 0 0 + c = 0 + -5 c = 0 + -5 Combine like terms: 0 + -5 = -5 c = -5 Simplifying c = -5Solution
c = {-10, -5}
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